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  1. #include <iostream>
  2. #include <cmath>
  3. using namespace std;
  4.  
  5. int convert_to_decimal (long long num, int base) {
  6. 	int decimal_value = 0;
  7. 	int power = 1;
  8.  
  9. 	while (num > 0) {
  10. 		int remainder = num % 10;
  11. 		num /= 10;
  12.  
  13. 		if (remainder >= base) {
  14. 			std::cout << "Error: Invalid digit for the given base" << std::endl;
  15. 			return -1;
  16. 		}
  17.  
  18. 		decimal_value += remainder * power;
  19. 		power *= base;
  20. 	}
  21. 	return decimal_value;
  22. }
  23.  
  24. int main() {
  25. 	long long number_in_other_base;
  26. 	int base;
  27.  
  28. 	std::cout <<"Enter the number in another base (e.g., 1011 for binary): ";
  29. 	std::cin >> base;
  30.  
  31. 	int result =   convert_to_decimal(number_in_other_base, base);
  32.  
  33. 	if (result != -1) {
  34. 		std::cout << number_in_other_base << " in base " << base << " is "
  35. 				  <<  result << " in decimal." << std::endl;
  36. 	}
  37.  
  38. 	return 0;
  39. }
Success #stdin #stdout 0.01s 5288KB
comments (?)
stdin 
Standard input is empty
stdout 
Enter the number in another base (e.g., 1011 for binary): 0 in base 32767 is 0 in decimal.
https://ideone.com/v9Fl06
language:
C++ (gcc 8.3)
created:
2 days ago
visibility:
public

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