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  1. /******************************************************************************
  2.  
  3. Welcome to GDB Online.
  4. GDB online is an online compiler and debugger tool for C/C++.
  5. Code, Compile, Run and Debug online from anywhere in world.
  6.  
  7. *******************************************************************************/
  8. #include <iostream>
  9. #include <bits/stdc++.h>
  10. using namespace std;
  11.  
  12. vector < vector < int > > finalVec;
  13.  
  14. void printArray(int p[], int n)
  15. {
  16. 	vector < int > vec;
  17.     for (int i = 0; i < n; i++)
  18.        vec.push_back(p[i]);
  19.     finalVec.push_back(vec);
  20.     return;
  21. }
  22.  
  23. void printAllUniqueParts(int n)
  24. {
  25.     int p[n]; // An array to store a partition
  26.     int k = 0;  // Index of last element in a partition
  27.     p[k] = n;  // Initialize first partition as number itself
  28.  
  29.     // This loop first prints current partition, then generates next
  30.     // partition. The loop stops when the current partition has all 1s
  31.     while (true)
  32.     {
  33.         // print current partition
  34.         printArray(p, k+1);
  35.  
  36.         // Generate next partition
  37.  
  38.         // Find the rightmost non-one value in p[]. Also, update the
  39.         // rem_val so that we know how much value can be accommodated
  40.         int rem_val = 0;
  41.         while (k >= 0 && p[k] == 1)
  42.         {
  43.             rem_val += p[k];
  44.             k--;
  45.         }
  46.  
  47.         // if k < 0, all the values are 1 so there are no more partitions
  48.         if (k < 0)  return;
  49.  
  50.         // Decrease the p[k] found above and adjust the rem_val
  51.         p[k]--;
  52.         rem_val++;
  53.  
  54.  
  55.         // If rem_val is more, then the sorted order is violeted.  Divide
  56.         // rem_val in differnt values of size p[k] and copy these values at
  57.         // different positions after p[k]
  58.         while (rem_val > p[k])
  59.         {
  60.             p[k+1] = p[k];
  61.             rem_val = rem_val - p[k];
  62.             k++;
  63.         }
  64.  
  65.         // Copy rem_val to next position and increment position
  66.         p[k+1] = rem_val;
  67.         k++;
  68.     }
  69. }
  70.  
  71.  
  72. int main()
  73.  
  74. {
  75.  
  76.     float mile = 1.609344f;
  77.  
  78.     float val = 20.0f * mile;
  79.  
  80.     for (int i = 0; i < 50; i++) {
  81.  
  82.         val += 2.0f * mile;
  83.  
  84.         printf("%i\n", (int)(val / 2.0f / mile) * 2);
  85.  
  86.     }
  87.  
  88.     for (int i = 0; i < 50; i++) {
  89.  
  90.         val -= 2.0f * mile;
  91.  
  92.         printf("%i\n", (int)(val / 2.0f / mile) * 2);
  93.  
  94.     }
  95.  
  96.  
  97.  
  98.     return 0;
  99.  
  100. }
Success #stdin #stdout 0s 5292KB
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https://ideone.com/qPHZYB
language:
C++14 (gcc 8.3)
created:
2 days ago
visibility:
public

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