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  1. #include <stdio.h>
  2.  
  3. int kaijo( int n)
  4. {
  5. if(n==1)
  6. return 1;
  7. else
  8. return kaijo(n-1)*n;
  9. }
  10.  
  11. int main()
  12. {
  13. printf("答えは:%d¥n", kaijo(4) );
  14. return 0;
  15. }
Success #stdin #stdout 0.01s 5196KB
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stdin
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Standard input is empty
stdout
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答えは:24¥n
https://ideone.com/eH3vh8
language:
C (gcc 8.3)
created:
4 days ago
visibility:
public

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