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  1. #include <stdio.h>
  2.  
  3. #define N 100
  4. int main() {
  5. 	double t[N],v[N];
  6. 	int i=0;
  7. 	while(scanf("%lf,%lf",&t[i],&v[i])==2&&i<N){
  8. 		i++;
  9. 	}
  10. 	printf("No.\t時間[s]\t電位[v]\n");
  11. 	int n=1;
  12. 	for(int j=1;j<i-1;j++){
  13. 		if(v[j]>v[j-1]&&v[j]>v[j+1]){
  14. 			printf("%d\t%lf\t%lf\n",n++,t[j],v[j]);
  15. 	}
  16. 	}
  17. 	return 0;
  18. }
  19.  
Success #stdin #stdout 0s 5324KB
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Standard input is empty
stdout
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No.	時間[s]	電位[v]
https://ideone.com/d3OEwh
language:
C (gcc 8.3)
created:
4 days ago
visibility:
public

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