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#include <iostream>
#include <bits/stdc++.h>
using namespace std;
 
vector < vector < int > > finalVec;
 
void printArray(int p[], int n)
{
	vector < int > vec;
    for (int i = 0; i < n; i++)
       vec.push_back(p[i]);
    finalVec.push_back(vec);
    return;
}
 
void printAllUniqueParts(int n)
{
    int p[n]; // An array to store a partition
    int k = 0;  // Index of last element in a partition
    p[k] = n;  // Initialize first partition as number itself
 
    // This loop first prints current partition, then generates next
    // partition. The loop stops when the current partition has all 1s
    while (true)
    {
        // print current partition
        printArray(p, k+1);
 
        // Generate next partition
 
        // Find the rightmost non-one value in p[]. Also, update the
        // rem_val so that we know how much value can be accommodated
        int rem_val = 0;
        while (k >= 0 && p[k] == 1)
        {
            rem_val += p[k];
            k--;
        }
 
        // if k < 0, all the values are 1 so there are no more partitions
        if (k < 0)  return;
 
        // Decrease the p[k] found above and adjust the rem_val
        p[k]--;
        rem_val++;
 
 
        // If rem_val is more, then the sorted order is violeted.  Divide
        // rem_val in differnt values of size p[k] and copy these values at
        // different positions after p[k]
        while (rem_val > p[k])
        {
            p[k+1] = p[k];
            rem_val = rem_val - p[k];
            k++;
        }
 
        // Copy rem_val to next position and increment position
        p[k+1] = rem_val;
        k++;
    }
}
 
 
int main()
 
{
 
    float mile = 1.609344f;
 
    float val = 20.0f * mile;
 
    for (int i = 0; i < 10; i++) {
 
        val += 2.0f * mile;
 
        printf("%i\n", (int)(val / 2.0f / mile) * 2);
 
    }
 
    for (int i = 0; i < 10; i++) {
 
        val -= 2.0f * mile;
 
        printf("%i\n", (int)(val / 2.0f / mile) * 2);
 
    }
 
 
 
    return 0;
 
}

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