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  1. # include<stdio.h>
  2.  
  3. int main(){
  4.     int y,m,d,days[]={0,31,28,31,30,31,30,31,31,30,31,30,31},total=0;
  5.     printf("需要判断的时间（年，月，日）：\n");
  6.     scanf("%d,%d,%d",&y,&m,&d);
  7.  
  8.     if ((y%4==0&&y%100!=0)||y%400==0)days[2]=29;
  9.     for (int i=0;i<m;i++)
  10.         total+=days[i];
  11.      total+=d;
  12.  
  13.     printf("这是%d年的第%d天",y,total);
  14.     return 0;
  15. }
  16.  
Success #stdin #stdout 0.01s 5320KB
comments (?)
stdin
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2025,5,20
stdout
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需要判断的时间（年，月，日）：
这是2025年的第140天
https://ideone.com/GJkGOU
language:
C (gcc 8.3)
created:
1 day ago
visibility:
public

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