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  1. #include<bits/stdc++.h>
  2. using namespace std;
  3. #define endl '\n'
  4. #define int long long
  5. const int MOD = pow(10,9)+7;
  6. const int MOD2 = 998244353;
  7. const int INF = LLONG_MAX/2;
  8.  
  9. int primes[1000000];
  10.  
  11. void seive(){
  12.     fill(primes, primes + 1000000, 1);
  13.     primes[0] = primes[1] = 0;
  14.     for(int i = 2 ; i*i < 1000000 ; i++){
  15.         if(primes[i]){
  16.             for(int j = i*i ; j < 1000000 ; j += i){
  17.                 primes[j] = 0;
  18.             }
  19.         }
  20.     }
  21.     for(int i = 1 ; i < 1000000 ; i++){
  22.         primes[i] += primes[i-1];
  23.     }
  24. }
  25. int factorial(int n){
  26.     if(n==0){
  27.         return 1;
  28.     }
  29.     return (n*(factorial(n-1)))%MOD;
  30. }
  31. bool isPrime(int n){
  32.     if(n <= 1) return false;
  33.     for(int i = 2 ; i*i <= n ; i++){
  34.         if(n % i == 0) return false;
  35.     }
  36.     return true;
  37. }
  38.  
  39. int power(int a, int b){
  40.     if(b == 0) return 1;
  41.     a %= MOD;
  42.     int value = power(a, b / 2);
  43.     if(b % 2 == 0){
  44.         return (value * value) % MOD;
  45.     } else {
  46.         return ((value * value) % MOD * (a % MOD)) % MOD;
  47.     }
  48. }
  49.  
  50. int gcd(int a, int b){
  51.     if(a == 0) return b;
  52.     return gcd(b % a, a);
  53. }
  54. void solve() {
  55.     int n1,m1;
  56.     cin>>n1>>m1;
  57.     vector<int>A[n1+1];
  58.     int value[n1+1];
  59.     for(int i = 0 ; i<m1 ; i++){
  60.         int a,b;
  61.         cin>>a>>b;
  62.         A[a].push_back(b);
  63.         A[b].push_back(a);
  64.     }
  65.     for(int i = 1 ; i<=n1 ; i++){
  66.         cin>>value[i];
  67.     }
  68.     int d;
  69.     cin>>d;
  70.     queue<int>q;
  71.     int visited[n1+1] = {0},visited2[n1+1] = {0};
  72.     int level[n1+1] = {0},level2[n1+1] = {0};
  73.     int five[n1+1] = {0},five2[n1+1] = {0};
  74.     int ways[n1+1] = {0};
  75.     visited[d] = 1;
  76.     if(value[d]==5){
  77.         five[d] = 1;
  78.     }
  79.     q.push(d);
  80.     while(!q.empty()){
  81.         int node = q.front();
  82.         q.pop();
  83.         for(auto node1 : A[node]){
  84.             if(!visited[node1]){
  85.                 q.push(node1);
  86.                 visited[node1] = 1;
  87.                 level[node1] = level[node]+1;
  88.                 if(value[node1]==5){
  89.                     five[node1] = 1+five[node];
  90.                 }
  91.                 else{
  92.                     five[node1] = five[node];
  93.                 }
  94.             }
  95.             else{
  96.                 if((level[node]+1)==(level[node1])){
  97.                     if(value[node1]==5){
  98.                         five[node1] = max((1+five[node]),five[node1]);
  99.                     }
  100.                     else{
  101.                         five[node1] = max(five[node],five[node1]);
  102.                     }
  103.                 }
  104.             }
  105.         }
  106.     }
  107.     visited2[d] = 1;
  108.     ways[d] = 1;
  109.     q.push(d);
  110.     while(!q.empty()){
  111.         int node = q.front();
  112.         q.pop();
  113.         for(auto node1 : A[node]){
  114.             if(!visited2[node1]){
  115.                 q.push(node1);
  116.                 level2[node1] = level2[node]+1;
  117.                 if(value[node1]==5){
  118.                     five2[node1] = 1+five2[node];
  119.                 }
  120.                 else{
  121.                     five2[node1] = five2[node];
  122.                 }
  123.                 if(five2[node1] == five[node1]){
  124.                     ways[node1] = ways[node];
  125.                 }
  126.                 visited2[node1] = 1;
  127.             }
  128.             else{
  129.                 if((level2[node]+1)==(level2[node1])){
  130.                     if(value[node1]==5){
  131.                         five2[node1] = max((1+five2[node]),five2[node1]);
  132.                     }
  133.                     else{
  134.                         five2[node1] = max(five2[node],five2[node1]);
  135.                     }
  136.                     if(five2[node1]==five[node1]){
  137.                         ways[node1] = ways[node1] + ways[node];
  138.                     }
  139.                 }
  140.             }
  141.         }
  142.     }
  143.     for(int i = 1 ; i<n1+1 ; i++){
  144.         cout<<"No of paths having shortest length from node 1 to node "<<i<<" and maximum no of 5s are : "<<ways[i]<<endl;
  145.     }
  146. }
  147.  
  148. signed main(){
  149.     ios::sync_with_stdio(false); cin.tie(NULL);
  150.     //int t;
  151.     //cin >> t;
  152.     //while(t--){
  153.         solve();
  154.     //}
  155.     return 0;
  156. }
Success #stdin #stdout 0s 5324KB
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stdin
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6 7
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stdout
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No of paths having shortest length from node 1 to node 1 and maximum no of 5s are : 1
No of paths having shortest length from node 1 to node 2 and maximum no of 5s are : 1
No of paths having shortest length from node 1 to node 3 and maximum no of 5s are : 1
No of paths having shortest length from node 1 to node 4 and maximum no of 5s are : 2
No of paths having shortest length from node 1 to node 5 and maximum no of 5s are : 1
No of paths having shortest length from node 1 to node 6 and maximum no of 5s are : 3
https://ideone.com/9MYoTA
language:
C++14 (gcc 8.3)
created:
2 days ago
visibility:
public

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