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  1. #include<bits/stdc++.h>
  2. using namespace std;
  3. #define endl '\n'
  4. #define int long long
  5. const int MOD = pow(10,9)+7;
  6. const int MOD2 = 998244353;
  7. const int INF = LLONG_MAX/2;
  8.  
  9. int primes[1000000];
  10.  
  11. void seive(){
  12. fill(primes, primes + 1000000, 1);
  13. primes[0] = primes[1] = 0;
  14. for(int i = 2 ; i*i < 1000000 ; i++){
  15. if(primes[i]){
  16. for(int j = i*i ; j < 1000000 ; j += i){
  17. primes[j] = 0;
  18. }
  19. }
  20. }
  21. for(int i = 1 ; i < 1000000 ; i++){
  22. primes[i] += primes[i-1];
  23. }
  24. }
  25. int factorial(int n){
  26. if(n==0){
  27. return 1;
  28. }
  29. return (n*(factorial(n-1)))%MOD;
  30. }
  31. bool isPrime(int n){
  32. if(n <= 1) return false;
  33. for(int i = 2 ; i*i <= n ; i++){
  34. if(n % i == 0) return false;
  35. }
  36. return true;
  37. }
  38.  
  39. int power(int a, int b){
  40. if(b == 0) return 1;
  41. a %= MOD;
  42. int value = power(a, b / 2);
  43. if(b % 2 == 0){
  44. return (value * value) % MOD;
  45. } else {
  46. return ((value * value) % MOD * (a % MOD)) % MOD;
  47. }
  48. }
  49.  
  50. int gcd(int a, int b){
  51. if(a == 0) return b;
  52. return gcd(b % a, a);
  53. }
  54. void dfs(int node , vector<int>A[] , int visited[] , int height[] , int parent[]){
  55. visited[node] = 1;
  56. for(auto node1 : A[node]){
  57. if(!visited[node1]){
  58. parent[node1] = node;
  59. dfs(node1,A,visited,height,parent);
  60. }
  61. }
  62. int h = 0;
  63. for(auto node1 : A[node]){
  64. if(parent[node1]!=node1){
  65. h = max(height[node1],h);
  66. }
  67. }
  68. height[node] = 1+h;
  69. }
  70. void solve() {
  71. int n1;
  72. cin>>n1;
  73. vector<int>A[n1+1];
  74. int visited[n1+1] = {0};
  75. int height[n1+1] = {0};
  76. int parent[n1+1] = {0};
  77. for(int i = 0 ; i<n1-1 ; i++){
  78. int a,b;
  79. cin>>a>>b;
  80. A[a].push_back(b);
  81. A[b].push_back(a);
  82. }
  83. dfs(1,A,visited,height,parent);
  84. for(int i = 1 ; i<=n1 ; i++){
  85. cout<<"Height of node "<<i<<" is : "<<height[i]<<endl;
  86. }
  87. }
  88.  
  89. signed main(){
  90. ios::sync_with_stdio(false); cin.tie(NULL);
  91. //int t;
  92. //cin >> t;
  93. //while(t--){
  94. solve();
  95. //}
  96. return 0;
  97. }
Success #stdin #stdout 0.01s 5288KB
stdin
5
1 2
2 3 
3 4 
1 5 
stdout
Height of node 1 is : 4
Height of node 2 is : 3
Height of node 3 is : 2
Height of node 4 is : 1
Height of node 5 is : 1