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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4. 	int T[11]={3,8,2,4,7,6,5,9,0,1};
  5. 	int n=10;
  6. 	int x;
  7. 	scanf("%d",&x);
  8. 	int i;
  9.     int last = T[n - 1];
  10.     T[n - 1] = x;
  11.  
  12.     i = 0;
  13.     while (T[i] != x) {
  14.         i++;
  15.     }
  16.  
  17.     // 元の値を戻す
  18.     T[n - 1] = last;
  19.  
  20.     if (i < n - 1 || T[n - 1] == x) {
  21.         printf("Found at %d\n", i + 1); 
  22.     } else {
  23.         printf("Not found\n");
  24.     }
  25. 	return 0;
  26. }
  27.  
Success #stdin #stdout 0s 5308KB
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Found at 7
https://ideone.com/0gYFrR
language:
C (gcc 8.3)
created:
21 hours ago
visibility:
public

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